Optimal. Leaf size=131 \[ \frac{2 B n \text{PolyLog}\left (2,\frac{b (c+d x)}{d (a+b x)}\right ) \left (B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A\right )}{b}+\frac{2 B^2 n^2 \text{PolyLog}\left (3,\frac{b (c+d x)}{d (a+b x)}\right )}{b}-\frac{\log \left (1-\frac{b (c+d x)}{d (a+b x)}\right ) \left (B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A\right )^2}{b} \]
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Rubi [A] time = 0.504468, antiderivative size = 227, normalized size of antiderivative = 1.73, number of steps used = 10, number of rules used = 8, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.242, Rules used = {6742, 2488, 2411, 2343, 2333, 2315, 2506, 6610} \[ \frac{2 A B n \text{PolyLog}\left (2,\frac{b c-a d}{d (a+b x)}+1\right )}{b}+\frac{2 B^2 n \text{PolyLog}\left (2,\frac{b c-a d}{d (a+b x)}+1\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{b}+\frac{2 B^2 n^2 \text{PolyLog}\left (3,\frac{b c-a d}{d (a+b x)}+1\right )}{b}+\frac{A^2 \log (a+b x)}{b}-\frac{2 A B \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{b}-\frac{B^2 \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{b} \]
Antiderivative was successfully verified.
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Rule 6742
Rule 2488
Rule 2411
Rule 2343
Rule 2333
Rule 2315
Rule 2506
Rule 6610
Rubi steps
\begin{align*} \int \frac{\left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2}{a+b x} \, dx &=\int \left (\frac{A^2}{a+b x}+\frac{2 A B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{a+b x}+\frac{B^2 \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{a+b x}\right ) \, dx\\ &=\frac{A^2 \log (a+b x)}{b}+(2 A B) \int \frac{\log \left (e (a+b x)^n (c+d x)^{-n}\right )}{a+b x} \, dx+B^2 \int \frac{\log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{a+b x} \, dx\\ &=\frac{A^2 \log (a+b x)}{b}-\frac{2 A B \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{b}-\frac{B^2 \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{b}+\frac{(2 A B (b c-a d) n) \int \frac{\log \left (-\frac{b c-a d}{d (a+b x)}\right )}{(a+b x) (c+d x)} \, dx}{b}+\frac{\left (2 B^2 (b c-a d) n\right ) \int \frac{\log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{(a+b x) (c+d x)} \, dx}{b}\\ &=\frac{A^2 \log (a+b x)}{b}-\frac{2 A B \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{b}-\frac{B^2 \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{b}+\frac{2 B^2 n \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \text{Li}_2\left (1+\frac{b c-a d}{d (a+b x)}\right )}{b}+\frac{(2 A B (b c-a d) n) \operatorname{Subst}\left (\int \frac{\log \left (-\frac{b c-a d}{d x}\right )}{x \left (\frac{b c-a d}{b}+\frac{d x}{b}\right )} \, dx,x,a+b x\right )}{b^2}-\frac{\left (2 B^2 (b c-a d) n^2\right ) \int \frac{\text{Li}_2\left (1+\frac{b c-a d}{d (a+b x)}\right )}{(a+b x) (c+d x)} \, dx}{b}\\ &=\frac{A^2 \log (a+b x)}{b}-\frac{2 A B \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{b}-\frac{B^2 \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{b}+\frac{2 B^2 n \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \text{Li}_2\left (1+\frac{b c-a d}{d (a+b x)}\right )}{b}+\frac{2 B^2 n^2 \text{Li}_3\left (1+\frac{b c-a d}{d (a+b x)}\right )}{b}-\frac{(2 A B (b c-a d) n) \operatorname{Subst}\left (\int \frac{\log \left (-\frac{(b c-a d) x}{d}\right )}{\left (\frac{b c-a d}{b}+\frac{d}{b x}\right ) x} \, dx,x,\frac{1}{a+b x}\right )}{b^2}\\ &=\frac{A^2 \log (a+b x)}{b}-\frac{2 A B \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{b}-\frac{B^2 \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{b}+\frac{2 B^2 n \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \text{Li}_2\left (1+\frac{b c-a d}{d (a+b x)}\right )}{b}+\frac{2 B^2 n^2 \text{Li}_3\left (1+\frac{b c-a d}{d (a+b x)}\right )}{b}-\frac{(2 A B (b c-a d) n) \operatorname{Subst}\left (\int \frac{\log \left (-\frac{(b c-a d) x}{d}\right )}{\frac{d}{b}+\frac{(b c-a d) x}{b}} \, dx,x,\frac{1}{a+b x}\right )}{b^2}\\ &=\frac{A^2 \log (a+b x)}{b}-\frac{2 A B \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{b}-\frac{B^2 \log \left (-\frac{b c-a d}{d (a+b x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{b}+\frac{2 A B n \text{Li}_2\left (\frac{b (c+d x)}{d (a+b x)}\right )}{b}+\frac{2 B^2 n \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \text{Li}_2\left (1+\frac{b c-a d}{d (a+b x)}\right )}{b}+\frac{2 B^2 n^2 \text{Li}_3\left (1+\frac{b c-a d}{d (a+b x)}\right )}{b}\\ \end{align*}
Mathematica [B] time = 0.180241, size = 269, normalized size = 2.05 \[ \frac{2 A B n \text{PolyLog}\left (2,\frac{d (a+b x)}{a d-b c}\right )+2 B^2 n \text{PolyLog}\left (2,\frac{b (c+d x)}{d (a+b x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )+2 B^2 n^2 \text{PolyLog}\left (3,\frac{b (c+d x)}{d (a+b x)}\right )+A^2 \log (a+b x)-2 A B \log \left (\frac{a d-b c}{d (a+b x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )-A B n \log ^2\left (\frac{a d-b c}{d (a+b x)}\right )-2 A B n \log \left (\frac{a d-b c}{d (a+b x)}\right ) \log \left (\frac{b (c+d x)}{b c-a d}\right )-B^2 \log \left (\frac{a d-b c}{d (a+b x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{b} \]
Antiderivative was successfully verified.
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Maple [F] time = 2.042, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{bx+a} \left ( A+B\ln \left ({\frac{e \left ( bx+a \right ) ^{n}}{ \left ( dx+c \right ) ^{n}}} \right ) \right ) ^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{B^{2} \log \left (b x + a\right ) \log \left ({\left (d x + c\right )}^{n}\right )^{2}}{b} + \frac{A^{2} \log \left (b x + a\right )}{b} - \int -\frac{B^{2} b c \log \left (e\right )^{2} + 2 \, A B b c \log \left (e\right ) +{\left (B^{2} b d x + B^{2} b c\right )} \log \left ({\left (b x + a\right )}^{n}\right )^{2} +{\left (B^{2} b d \log \left (e\right )^{2} + 2 \, A B b d \log \left (e\right )\right )} x + 2 \,{\left (B^{2} b c \log \left (e\right ) + A B b c +{\left (B^{2} b d \log \left (e\right ) + A B b d\right )} x\right )} \log \left ({\left (b x + a\right )}^{n}\right ) - 2 \,{\left (B^{2} b c \log \left (e\right ) + A B b c +{\left (B^{2} b d \log \left (e\right ) + A B b d\right )} x +{\left (B^{2} b d n x + B^{2} a d n\right )} \log \left (b x + a\right ) +{\left (B^{2} b d x + B^{2} b c\right )} \log \left ({\left (b x + a\right )}^{n}\right )\right )} \log \left ({\left (d x + c\right )}^{n}\right )}{b^{2} d x^{2} + a b c +{\left (b^{2} c + a b d\right )} x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{B^{2} \log \left (\frac{{\left (b x + a\right )}^{n} e}{{\left (d x + c\right )}^{n}}\right )^{2} + 2 \, A B \log \left (\frac{{\left (b x + a\right )}^{n} e}{{\left (d x + c\right )}^{n}}\right ) + A^{2}}{b x + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \log \left (\frac{{\left (b x + a\right )}^{n} e}{{\left (d x + c\right )}^{n}}\right ) + A\right )}^{2}}{b x + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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